I want a detailed explanation of this problem, especially what formulas are used

Call: Im(formula = Grade ~ gender + Announcements. View + Discussion. Times + Student. Absence. Days, data = oh) Residuals : Min 1Q Median 30 Max -19.878 -5.551 1.091 6.088 11.294 Coefficients: Estimate Std. Error t value Pr(>Itl) (Intercept) 88. 581444 0.909208 97.427 100. p - value = 0.5247 Since p-value > 5%, we fail to reject Ho. Thus, we conclude that the discussion time is not a significant factor for the grade c) What is the 95% confidence interval for Ba ? Margin of Error = e = [ value x Std. Error Zayat X 0.0139 = 1.96 x 0.0139 = 0.0272 Thus, 95%% Cl for Ry is fa t . = 0.0397 1 0.0272 = [0.0125, 0.0669] ) interpret the meaning of the soe ants of X1 and X4 keep everything else go have 1.0378 average grade lower than the female students, Keep everything else constant, one ment will bring students 0.0397 higher on. au 2) Atsuming we have a fan nes is 75 and ber views of ann ent is on wina let's grade? Based on your reg prediction? 885814 4 0:0397 x 40 + 2083 x 25 + 15674 = 92:35