I want a solution using basic methods ONLY , or the dislike is on the way

Q5: A hot fluid is cooled down in a counter-current heat exchanger by using cooling water. The hot liquid enters the exchanger at Th=85C (i.e., Th(0)=85C ). While cooling water enters the exchanger from the opposite side (z=1) and leaves at z=0 with a temperature Tc(0)=55C. The temperature profile along the length (z) for each liquid can be represented by the following system of equations. dzdTh=mhCph2rh(TcTh)dzdTc=mcCpc2rh(ThTc) Tc is temperature of cold fluid, Th is the temperature of hydrocarbon fluid, h is the heat transfer coefficient, CPhPh and CPCPC the heat capacities of hot and cold fluid respectively. The values for parameters are given as h=260(w/m2/C);Cph=2200(J/kg/C);Cpc=2650(J/kg/C); mh=0.18(kg/s);mc=0.26(kg/s); and r=0.75m. Solve for the following 1. The temperature profile along the length (z) of heat exchanger for both fluids and plot the temperature profiles of each stream against z in the same figure. 2. Find out the exit temperature of hot stream. 3. Find out the temperature Th and Tc at z=0.7m