I want to make a sweater where the pattern savs I need 2800 meters of yarn. The yarn that I want to use comes in skeins that average 300 meters each. The standard deviation is 100 meters. I bought 9 skeins and I think it should be enough. What is the probability that I will have enough yarn? Hint: the formula in the Central Limit Theorem for normal distributions with mean u and standard deviation o is: