I was able to find the square form which is f(x)=3(x+2)^2-5And the vertex which is (-2,-5)Please find and show work for the x intercept and say what the answer did wrong

2. Part 2 - Find the error(s) and solve the problem correctly. Express the following in completed square form to find the vertex and the x-intercepts. f(x) = 3x2 +12x +7 Answer: Complete the square to find the vertex. 3(12 + 12x) +7 =0 3(x2 4 12x + 36) +7+ 36 =0 3(x +6)2 47+36=0 3(x + 6)2+ 29 =0 vertex = (-6, 29) Solve for x to get x-intercepts. 3(2 +6)- -29 (2 + 6)'= - 29 3 29 (a +6)=#1 3 29 6 3