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I was hoping you could help me check my answers, for an I got 8.00 (I can't tell if 7.80 would be more appropriate though?),
I was hoping you could help me check my answers, for an I got 8.00 (I can't tell if 7.80 would be more appropriate though?), and for b I got 0, but I'm not sure if the limit exists there at all? And then for question 3, I included the solutions as I did them above, but I'm not sure if I did them right or if this is complete enough. If incorrect please include alternate solutions.
1. Tony and Steve went on a hike in the forest and they are lost in the woods. Tony injured himself and can't walk anymore. Tony took out a map trying to figure out where he is. He saw two wooden paths and wondered if they are continuous. [5] p(t) 10- O a 61 2 W 4 a) Find lim f(x). x-3 b) Find lim f(x). x 3+3. As it gets darker outside, Steve is lost in the woods, and he calls for help. A helicopter at Point A (6, 9, 3) moves with constant velocity in a straight line. 10 minutes later it is at Point B (3, 10, 2.5). Distances are in kilometres. a) Find Vector AB. b) Find the helicopter's speed, in km/hour. C) Determine the vector equation of the straight line path of the helicopter. Steve is at point U (7, 2, 4), determine the shortest distance from point U to the path of the helicopter [9]c) Vector equation of line A + (CAB) = ( 6, 9, 3) + ( C - 3, 1,-0-5) = ( 6- 34, 9+t, 3-0.5t) d U( 7 , 2 , 4) Shortest distance = perpendicular distance of line path from pointShorrtest = UA x ABl distance I AB JA = ( 7 - 6 , 2 - 9 , 4 - 3 ) = ( 1 , - 7, 1 ) JAX AB = i K - - - 7 -3 = i ( 3.5-1) - j ( - 0. 5+ 3) + k(1-21 ) = 2.5) - 2.5j - 20K. |JA + AB = / ( 2. 5 ) 2 + ( - 2-5 ) ? + ( - 20 ) 2. = 1/412.5 AB = 10. 25 shortest distance = 6. 3438 kmStep by Step Solution
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