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I was wondering if someone can help me with the Bayes formula for P (A|B) but expanding it in a Taylor Series for P (A).
I was wondering if someone can help me with the Bayes formula for P(A|B) but expanding it in a Taylor Series for P(A).
(For reference, P(A|B) = P(B|A)P(A) / ( P(B|A)P(A) + P(B|Ac)P(Ac))
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