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'A certain genetic characteristic of a particular plant can appear In one ofthree forrns (phenotypes). A researcher has developed a theory, according to which the hypothesized proportions arepI 0.25, p2 .25. A random sample of 200 plants yields ,2 : 5.4. m USE s (a) carry out a test of the null hypothesis that the theory is correct, using level of signicance a : n.n5. .50, and Q3 What is the psvalue for the test? [Use technology to calculate the psvalue. Round your answer to five decimal places.) \\:| what can you conclude? Prva lue O Fail to reject H\". We have convincing evidence that the theory is incorrect. O Reject HD We have convincing evidence that the theory is incorrect. O Rejed HD We do not have convincing evidence evidence that the theory is incorrect. O Fail to reject H\". We do not have convincing evidence that the theory is incorrect. (b) Suppose that a random sample of 300 plants had resulted in the same value of '3. How would the analysis and conclusion differ from those in part (a)? O The previous analysis yielded a signicant result and the null hypothesis was rejeded. The new analysis would not yield a significant result and the null hypothesis would fail to he rejeded. O The analysis and conclusions would not change. 0 The previous analysis did not yield a signicant result and the null hypothesis failed to pe rejected. The new analysis would yield a signieant result and the null hypothesis would be rejected. 0 The previous analysis yielded a signicant result and the null hypothesis failed to he rejected The new analysis would not yield a signicant result and the null hypothesis would pe rejected. 0 The previous analysis did not yield a signicant result and the null hypothesis was rejected The new analysis would yield a signicant result and the null hypothesis would fail to he rejected