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If 1.0 gram of an unknown acid requires exactly 40.00 mL of 0.25MNaOH to reach the equivalence point, what is the formula weight for the

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If 1.0 gram of an unknown acid requires exactly 40.00 mL of 0.25MNaOH to reach the equivalence point, what is the formula weight for the unknown acid? A . 50 grams per mole B. 80 grams per mole C. 100 grams per mole D. 125 grams per mole

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