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If 1.00 mol of argon is placed in a 0.500-L container at 28.0 C , what is the difference between the ideal pressure (as predicted
If 1.00 mol of argon is placed in a 0.500-L container at 28.0 C , what is the difference between the ideal pressure (as predicted by the ideal gas law) and the real pressure (as predicted by the van der Waals equation)? For argon, a=1.345(L2atm)/mol^2 and b=0.03219L/mol
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