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If 180. metric tons (metric ton = 10 kg) 0.75% S coal is burned, (a) how many kg SO would be produced, (b) how

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If 180. metric tons (metric ton = 10 kg) 0.75% S coal is burned, (a) how many kg SO would be produced, (b) how much CaCO3 would be needed for a scrubber (100% capture), and (c) how much product would be formed (assume 100% CaSO4)? Note that the calculations are all just basic stoichiometry.

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