If $26\mathrm{.}02mL$ of $0\mathrm{.}2298$MKOH is required to completely neutralize $23\mathrm{.}00mL$ of a $C{H}_3\frac{C}{O}OH$ solution, what is the molarity of the acetic acid solution? $C{H}_3\frac{C}{O}OH(aq)+$KOH$(aq)C{H}_3\frac{C}{O}OK(aq)+H_{2}O(l)$

molarity $=$ M