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If 3/(2+ cos ?+i sin ?) = a+ib, then [(a-2) 2 +b 2 ] is (a) 0 (b) 1 (c) -1 (d) 2

If 3/(2+ cos ?+i sin ?) = a+ib, then [(a-2)2+b2] is

(a) 0

(b) 1

(c) -1

(d) 2

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