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If a > 0 and b>0 and a +b = 23 ab prove that loge (a+b) = 1 (log, a + log, b) 2

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If a > 0 and b>0 and a +b = 23 ab prove that loge (a+b) = 1 (log, a + log, b) 2 Hint: start with (a+b) = a+2ab+b

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