If a bowling ball is dropped from a height of 75 feet, what is the velocity of the ball (in feet/sec) upon impact? [Do not include units and round your answer to the nearest hundredth]12 Drop height = S= 75ft. [ 1 me 3 28 08 9 ft ] Initial velocity= u= oft/s. Qu= off/s Final velocity at impact = V . Acceleration g 2 9. 8 m /2 5275f1 32 . 15 32 ft / 1 2 V V = ? N 2 - y - 295 D V 2 = 2 95 2 ) vz V 2 X 32. 15 22 x 75 V = 69. 4465 ft /s. V- 69 . 95 ft/s . ( and ) The problem is with unit conversion, different people use different no. of precision to 8 convert 'n' to ift', Due to that the ultimate conversion factor varies by a small margin, that's what creates the discripany in the final solution. Also, remember to exclude the unit as advised by the question in the final