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If a cannonball is shot directly upward with a velocity of 176 ft/sec, its height, in feet, above the ground after t seconds is given

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If a cannonball is shot directly upward with a velocity of 176 ft/sec, its height, in feet, above the ground after t seconds is given by s(t) = 176t- 16t . Find the velocity and the acceleration after t seconds. When does the cannonball reach its maximum height? What is the maximum height the cannonball reaches? When does it hit the ground? . . . The velocity after t seconds is v(t) =

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