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If a golfer launches a shot that is 39.1 degrees with respect to the horizontal, what initial speed, in m/s, must she give the ball
If a golfer launches a shot that is39.1degrees with respect to the horizontal, what initial speed, in m/s, must she give the ball to land it on the green? |
and part b as well pls
The tee of the world's longest par 3 sits atop South Africa's Hanglip Mountain at 400.0 m above the green and can only be reached by helicopter. The horizontal distance to the green is 359.0 m. Neglect air resistance. Torabzadeh, Kayvon - kayvon.torabzadeh@doane.edu @theexpertta.com - tracking id: 9N69-A4-C7-42-9888-44116. In accordance with Expert TA's Terms of Service. copying this information to any solutions sharing website is strictly forbidden. D may result in termination of your Expert TA Account. Part (a) If a golfer launches a shot that is 39.1 degrees with respect to the horizontal, what initial speed, in m/s, must she give the ball to land it on the green? Grade Summary V = 47.21 Deductions Potential sin() cos() tan() 7 8 9 HOME Submissions Attempt(s) Remaini cotan() asin() acos() TA A 4 5 6 0% Deduction per A detailed view atan() acotan() sinh() 2 3 cosh() tanh() cotanh() + 0 END UAWNH O Degrees O Radians VO BACKSPACE DEL CLEAR Submit Hint Feedback I give up! 992 Submission(s) Remaining Hints: 1 for a 0% deduction. Hints remaining: 0 Feedback: 0% deduction per feedback. -If upward is the positive y direction, then ay = -9.80 m/s and ax = 0. The x and y components of the initial velocity are vox = vocose and Voy = vosin0, respectively. Solve for time in x = voxt and substitute into y = yo + voyt + (1/2)a,12. Solve for vo. Part (b) What is the time, in seconds, that it takes the ball to reach the greenStep by Step Solution
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