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If a primary memory is of size 128MB and the supercell size is 8 bits, then what is the minimum number of bits in an
If a primary memory is of size 128MB and the supercell size is 8 bits, then what is the minimum number of bits in an address?
Note: this means that the memory is of size 27 * 220 * 23 bits (because a M is 220 and a byte is 8 bits) and every 8 bits in that memory has an address (because this is the size of a supercell).
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