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If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h

If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation hequals=minus16t squaredt2plus+vtplus+s,

where h is in feet. If the object is propelled from a height of 12

feet with an initial velocity of 96

feet per second, its height h is given by the equation hequals=minus16t squaredt2plus+96tplus+12.

After how many seconds is the height 152

feet?

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