If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation he = 16t^2+vt+s,

where h is in feet. If the object is propelled from a height of 44

feet with an initial velocity of 64

feet per second, its height h is given by the equation h equals16t^2+64t+44.

After how many seconds is the height 32

feet?