If an object is propelled upward from a height of s feet at an initial velocity of v feet persecond, then its height h after t seconds is given by the equation hequals

=minus

16t squared

t2plus

+vtplus

+s, where h is in feet. If the object is propelled from a height of 4

4 feet with an initial velocity of 64

64 feet persecond, its height h is given by the equation hequals

=minus

16t squared

t2plus

+64

64tplus

+4

4.

After how many seconds is the height 32

32 feet?