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If an object is thrown upward with an initial velocity of 256 ft/second, then its height after t seconds is given by the following equation.

If an object is thrown upward with an initial velocity of 256 ft/second, then its height after t seconds is given by the following equation.

h equals 256 t minus 32 t squaredh=256t32t2

a. Find the maximum height attained by the object.

b. Find the number of seconds it takes the object to hit the ground.

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