If any dimensions need to be added you're more then welcome as long as you define it. The question is how much force your body is exerting on the ground, while in triangle yoga pose, where one of the hand and both legs touching the ground. total ground force is 588 Newton, but find how it is distributed between Fg1, Fg2 and Fg3. Include any free body diagrams. Thanks !

TRIANGLE YOGA How much force body exerts on THE ARM 15? Ground? FARM FIND FG, , FG, , PGs V DB BODY WEIGHT - GO KG F BODY LEG 2 ARM W = GORG X 9.8 m/s z ARM 2 LeG 1 = 588 N FLA FLZ D = dI STANCE = DB = 10 cm X Ground DI = P2 = 5 cm 2 Da , = D G 2 = D = = 30 cm FOX DAI = DGZ ( ARM TOUCHES FLOOR ) FROMARM LEG & LEGZ to center SAME DISTANCE HINT : USO PRINCIPLE OF FORCE BALANCE AND MOMENTS M = FXd. 9 GRAVITY Y DISTANCE F = M G