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If dy/dt=(y5) 2 , then y(t)=5 is an equilibrium solution. Suppose y(t) is a solution with initial-value y(3)=7 . What we can conclude based off

If  dy/dt=(y−5)2, then  y(t)=5  is an equilibrium solution. Suppose  y(t)  is a solution with initial-value  y(3)=7  . What we can conclude based off of the theory? (Please choose only one best answer/option)

(a) y(t)-> 5 as t-> infinity

(b) y(t)-> infinity as t-> infinity

(c) y(t)-> 5 as t increases

(d) y(t)-> infinity as t Increases

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