If f (:5) is a polynomial of degree it, then any Taylor polynomial for f(:1:) of degree n 2 k is equal to f (:5). 2. Find the Taylor series centered at :L' = 0 for each of the following functions. Then nd interval of convergence. (3) ft?) = 8\"" (b) f(x) = ln(1 +12) (0) f0\") = 3111(3) (d) N?) = 803(3)