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If f(x) = log e ((1 x)/(1+x)), |x| < 1, then f(2x/(1+x 2 )) is equal to: (a) 2f(x) (b) 2f(x 2 ) (c)

If f(x) = loge((1 – x)/(1+x)), |x| < 1, then f(2x/(1+x2)) is equal to:

(a) 2f(x)

(b) 2f(x2)

(c) (f(x))2

(d) -2f(x)

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