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If n=1, terminate, If n=0 mod 2, set n/2 as n and repeat from step one, If n=1 mod 2, set 3n+1 as n and
If n=1, terminate, If n=0 mod 2, set n/2 as n and repeat from step one, If n=1 mod 2, set 3n+1 as n and repeat from step one. The guess that this algorithm will always terminate is known as what?
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