If the 2315 possible words are known, then one way to play the game is to

randomly select with equal probability and without replacement words from

this list until the correct word is chosen or six attempts have been made...whichever occurs first.

1. What is the probability we guess the correct word on the first attempt?

2. What is the probability we guess an incorrect word on the first attempt but the correct word on the second attemp?

3. Compute the probability the first two guesses are incorrect but the third guess is correct. (show your work)

4. The only way to lose at this game is to make 6 incorrect guesses. What then is the probability of winning using our method? (show your work)