For your initial post pick a combination of one of the following molecules, one mass quantity,...

 

  

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For your initial post pick a combination of one of the following molecules, one mass quantity, and one total solution volume from this table. You may not use the same combination as another student so be sure to read any existing peers postings before posting your own. Molecule Mass Volume NaCl 2 g 150 ml CaBr₂ 6g 3L Li;N 1 g 7 g 500 ml 14 L CaO For example, one possible combination would be 2 grams of NaCl in 500 ml of solution. Then, give each of the following for your unique combination being sure to show all of your work: %mass/volume concentration Molarity Osmolarity Course Mate Discussion For this post I chose Li3N, 7g, and 3L %mass/volume concentration: First I need to convert 3L into ml. I do that by multiplying 3 x 1000 which would equal 3000ml %mass/volume concentration (7g/3000ml) x 100 = 0.23% g/ml. Molarity: Molarity (M) moles/L. 20.82 g/mol (Li3) + 14.01 g/mol (N) = 34.83 g/mol Conversion factor: (34.83 g Li3N/ 1 mol Li3N). Convert from g to mol: 7 g Li3N x (1 mol Li3N/34.83 g Li3N)=0.201 mol Li3N Calculating L: M= mol/L M=0.201 mol Li3N/3L = 0.067 ML13N Osmolarity Li3N would break up into 4 molecules 4 x 0.067 M 0.268 Osm/L For your initial post pick a combination of one of the following molecules, one mass quantity, and one total solution volume from this table. You may not use the same combination as another student so be sure to read any existing peers postings before posting your own. Molecule Mass Volume NaCl 2 g 150 ml CaBr₂ 6g 3L Li;N 1 g 7 g 500 ml 14 L CaO For example, one possible combination would be 2 grams of NaCl in 500 ml of solution. Then, give each of the following for your unique combination being sure to show all of your work: %mass/volume concentration Molarity Osmolarity Course Mate Discussion For this post I chose Li3N, 7g, and 3L %mass/volume concentration: First I need to convert 3L into ml. I do that by multiplying 3 x 1000 which would equal 3000ml %mass/volume concentration (7g/3000ml) x 100 = 0.23% g/ml. Molarity: Molarity (M) moles/L. 20.82 g/mol (Li3) + 14.01 g/mol (N) = 34.83 g/mol Conversion factor: (34.83 g Li3N/ 1 mol Li3N). Convert from g to mol: 7 g Li3N x (1 mol Li3N/34.83 g Li3N)=0.201 mol Li3N Calculating L: M= mol/L M=0.201 mol Li3N/3L = 0.067 ML13N Osmolarity Li3N would break up into 4 molecules 4 x 0.067 M 0.268 Osm/L