If the series y(x) = x is a solution of the differential equation 2y" - 2xy' + 1y = 0, then C+2 n=0 (2(n-1))/(2(n+1)(n+2)) Cn, n = 1, 2,... C 1-1/(2(n+1)(n+2)) A general solution of the same equation can be written as y(x) = C0Y1(x) + CY2(x), where Y(x)=1+ anx", Y2(x) = n-2 00 1 = x + bx", n=2 Calculate 15 a3 04 b b3 b re 1