Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

If V varies from 0 to 7 2 5 , what is the value of X ( expressed to two decimal places ) when V

If V varies from 0 to 725, what is the value of X (expressed to two decimal places) when V is 725 given the following equations:
k =0.07
KC=0.05
CA0=0.3
FA0=3.5
The initial value of X=0, and the initial value of Y =1.If V varies from 0 to 725, what is the value of x(expressed to two decimal places) when V
is 725 given the following equations:
dxdV=-rFA0
dYdV=-*(1+*x)2*Y
r=-1*((k*CA0)(1+*x))((1-x)-(4*CA02*x3)((1+*x)2*KC))
k=0.07
KC=0.05
=0.001
CA0=0.3
=-0.3
FA0=3.5
The initial value of x=0, and the initial value of Y=1.
image text in transcribed

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

Elementary Principles of Chemical Processes

Authors: Richard M. Felder, Ronald W. Rousseau

3rd Edition

978-0471687573, 9788126515820, 978-0-471-4152, 0471720631, 047168757X, 8126515821, 978-0471720638

More Books

Students also viewed these Chemical Engineering questions

Question

=+b) Form the F-statistic by dividing the two mean squares.

Answered: 1 week ago