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If we accept that scalar multiplication is effectively multiplying each component of the vector by the scalar value, it becomes much more straightforward to multiply
If we accept that scalar multiplication is effectively multiplying each component of the vector by the scalar value, it becomes much more straightforward to multiply by more than just integer-valued scalars.
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Concepts In Analysis Geometry
Authors: J K Kashyap
1st Edition
9353146453, 9789353146450
