If we sample from a small finite population without replacement, the binomial distribution should not be used because the events are not independent. If sampling is done without replacement and the outcomes belong to one of two types, we can use the hypergeometric distribution. If a population has A objects of one type, while the remaining B objects are of the other type, and if n objects are sampled without replacement, then the probability of getting x objects of type A and

nx

objects of type B under the hypergeometric distribution is given by the following formula. In a lottery game, a bettor selects

four

numbers from 1 to

48

(without repetition), and a winning

four-number

combination is later randomly selected. Find the probabilities of getting exactly

two

winning numbers with one ticket. (Hint: Use

A=4,

B=44,

n=4,

and

x=2.)

P(x)=A!(Ax)!x!B!(Bn+x)!(nx)!(A+B)!(A+Bn)!n!

Question content area bottom

Part 1

P(2)=enter your response here