If x (t) = 3u (1), the output of the given system is observed to produce y(t) = 3u(t)- 3eu(t). If the input x (t) is delayed by 10, i.e. x (t) = 3u(t-10), which of the following is the output y(t)? Oy(t) = 3u (t-10) - 3e = 3u (t) y(t) = 3u(t-10) - 3e = 3u (1-10)