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if y=2x^2 -4, what it the inverse? I think the answer is y^-1= -sqrt x+4/2 such that x < 0 or y^-1 = -sqrt x+4/2

if y=2x^2 -4, what it the inverse?

I think the answer is y^-1= -sqrt x+4/2 such that x < 0

or y^-1 = -sqrt x+4/2 such that x > 0

(not sure if x<0 or x>0)

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