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If you were to find the focal point of a converging, or concave, mirror, it would be positive and half the radius of curvature. On

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If you were to find the focal point of a converging, or concave, mirror, it would be positive and half the radius of curvature. On the diagram below draw the three principal reflected rays from the object (the arrow in this case ;) which will indicate the position (d;), size (h;), orientation (upright or inverted), and nature (real or virtual) of the image formed. Label each value on the diagram and give the actual numerical values according to the symbols used in equations from the "Lenses & Mirrors Notes" document. (The three principal ravs for reflection/mirrors are thoroughly described in your text.) d. = 10cm f = 6cmLastly, for this simulation, move the object to the near focal point and draw the location of both the object and the image below. Add a ray diagram including the three principal rays.Next let us investigate the image formed by a converging, or convex, lens. On the diagram below draw the three principal refracted rays from the object (the arrow in this case ;) which will indicate the position (d;), size (h;), orientation (upright or inverted), and nature (real or virtual) of the image formed. Label each value on the diagram and give the actual numerical values according to the symbols used in equations from the "Lenses & Mirrors Notes" document. (The three principal rays for refraction/lenses are thoroughly described in your text.) d. = 10cm f= 6cmLastly let us do one exercise with a diverging lens which has a negative focal point. On the diagram below draw the at least two principal refracted rays from the object (the arrow in this case ;) which will indicate the position (d;), size (h;), orientation (upright or inverted), and nature (real or virtual) of the image formed. Label each value on the diagram and give the actual numerical values according to the symbols used in equations from the "Lenses & Mirrors Notes" document. (The three principal rays for refraction/lenses are thoroughly described in your text.) do = 10cm f= -6cmLenses and Mirrors Mirrors and Lenses: Thin lenses and mirrors follow the same relationship between focal length f, object distance s, and image distance s'. It is as follows: (1) The magnification of a lens or mirror is defined as the ratio of image height h' to object height h and is related to the object and image distances by: (2) The signs of the terms are defined by the following conventions: MIRRORS - expect light to reflect focal length, f Positive (+) converging Negative (-) diverging geometry concave mirror convex mirror image distance, s image real Image virtual ie. on same side as object ie. on opposite side as object LENSES- expect light to refract focal length, f Positive (+) converging Negative (-) diverging geometry convex lens concave lens image distance, s' Image real image virtual ie. on opposite side as object ie. on same side as object Both mirrors and lenses Positive (+) Negative (-) object distance, s object in front (the usual object in back assumption for our class!) Magnification, m Image is right-side-up Image is upside-down Chromatic Aberration. Glass is a dispersive medium - the index of refraction of the material is frequency dependent. As a result, different frequencies of light will form images at slightly different positions. Chromatic aberration is a distortion or imperfection in the image formed by a lens due to the focal length's dependence on the frequency of the incident light. Spherical Aberration. The derivation of the thin lens equation assumes the approximation that all angles are small. Light incident upon the outer edges of a large diameter lens may not fit this approximation. Spherical aberration is a distortion or imperfection in the image due to the fact that the focal length of the lens is different for light incident upon different parts of the lens

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