ii$)$ Consider the following two transactions:

T$31$: read$($A$)$;

read$($B$)$;

if A$=0$ then B $=$ B$+1$;

write$($B$)$;

T$32$: read$($B$)$;

read$($A$)$;

if B$=0$ then A $=$ A$+1$;

write$($A$)$;

Add lock and unlock instructions to transactions T$31$ and T$32,$ so that they observe the two$-$phase locking protocol. Can the execution of these transactions result in a deadlock?