ii. iii. the distance of car and instant. The velocity-time graph of an object moving along a straight line is The velocity-time graph of an object moving along a straight line is as shown below: an shown below: Calculate the distance covered by object between: a. b. the s the time whe a. (i) t=0 tot=5s A body stands on a cliff edge and throws a stone vertically upwards at time t (ii) t=0to t= 10 s. hand at 20 ms-1. Take the acceleration of the ball as 9.81 ms-2. Show that the equation for the displacement of the ball is: s=20t-4.9t What is the height of the stone 2.0s after release and 6.0s after release? When does the stone return to the level of the boy's hand? Assume the boy's hand does not move vertically after the ball is released. The graph in Figure shows the variation of velocity with time of two cars, A and B, which are travelling in the same direction over a period of time of 40 s. Car A, travelling at a constant velocity of 40 m s-1, overtakes car B at time t = 0. In order to catch up with car A, car B immediately accelerates uniformly for 20 s to reach a constant velocity of 50 m s-1. Calculate: [3+2] ii. () how far A travels during the first 20 s the acceleration and distance of travel of B during the first [2] 20s [3] determine the time at which the ball reaches its highest point show that the Velocity/ms! opp 80 of ec C ri C. the additional time taken for B to catch up with A [2] d. the distance each car will have then travelled since t = 0. [1] A hot-air balloon rises vertically. At time t = 0, a ball is released from t variation of the ball's velocity v with t. The ball hits the ground at t = 4.1 s. Explain how the graph shows that the acceleration of the ball is const 3. 5. Use the graph to: i. Fig.