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Figure 1 illustrates a common emitter amplifier using BC547. Calculate the resistance of R1, R2, Rc and Re to make an emitter current of about

Figure 1 illustrates a common emitter amplifier using BC547. Calculate the resistance of R1, R2, Rc and Re to make an emitter current of about 1 milli-amp by using the design notes below.
Figure 1 illustrates acommon emitter amplifier using BC547.Calculate the resistance of RI.R2.Re and Re to make an emiter current ofabout 1 milliamp by using the design motos below. Derige Notes Aim for about 10% of VOC across Re. Then choose an E12resistor value for Re to sxt the emittoreument to ImA. As the eminer resistor Re takes 10% of vec, the base voltage needsto be at about 27 volts to make the BUT operate in Ensure that the cument flow through the voltage dividerRI and R2is at least 10 times of the base cument (which also flows through resistor RI) as this tends to minimize the possibility thatthe base cument(when varying with AC) will affectthe biasing amangement Assume the cument gain of Bc347is 100. Make VCE about the same asthe voltagedrop across Re for a largest output swing, Which can be possible comect answer in the following options based on your design calculations?

The voltage gain, input and output resistance of the amplifier can be predicted from the AC equivalent circuit of the amplifier. Use the developed the AC equivalent circuit below to work out the the voltage gain, and input and output resistance. Choose the correct calculations for them from the following options. Ignore the output resistor r0 of the BJT and assume thermal voltage of the BJT is 25 mV.

The Figure below shows a BJT common collector amplifier as well as its AC equivalent circuit. Assume the RS of the FG is 50Ω, early voltage of the BJT is 45V, current gain β is 100, thermal voltage VT is 25mV, and biasing DC current IC=1mA. Calculate r0, rπ, and further input and output resistances Rin and Rout illustrated in the equivalent circuit. Which answers below are correct?


 

Figure i illustrates a common emitter amplifler using BCS47. Calculate the resistance of R1, R2, Re and Re to make an emitter curent of about I milli-amp by using the design notes below. Vo Ge Design Noter Aim for about l10% of VCC across Re. Then choose an E12 resistor value for Re to set the emimer current to ImA. As the emiter sesistor Re takes 10% of Vec, the base volhage needs to be at about 2.7 volts to make the BJT operate in conduction mode. Ensure that the curent flow through the voltage divider Ri and R2 is at least 10 times of the base current (which also flows through resistoe RI) as this tends to minimize the possibility that the base curent (uhen varying with AC) will affeet the biasing amangement. Assume the current gain Bof BCS47 is 100. Make VCE sbout the same as the voltage drop acros Re for a largest output swing Which can be possible correet answers in the following options based on your design caleulations? RI-1SI, R2-27 ka, Re-, Re2 ka RI-IRO, R2-a. Re-22 ka Re-0 OB RI-22. R2-33 AO. Re-22. Re-10 k Ri-O, R2-27 R. Re- , Re82 ka. RI-1ONI. R2-27 LO, Re-1, Re-t0 OD. DE

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