I'm not sure how to solve this

8. CalC16b17s 10 pts possible Calculate the value of the double integral 4x cos(z + y) dx dy 0 1. 1 = 4(V2- 1) - 57(2 - V2) 1 = JA when A is the rectangle O 2. 1 = TV2-4(V2-1) { ( I , y ) : 0 S I S -, OSUS-). 3. I = TV2+ 4(V2 -1) N 0 4. 1 = 4(V2 + 1) - 51(2+ V2) 5. 1 = 4(V2 - 1) + 27(2-V2) 6. I = TV2 -4(V2+ 1)