I'm not sure if I'm correct, please assist me with this question.

The information as follows,

Mean= $6058

Standard deviation= $500

Normally distributed

Question: what is the probability the monthly pay is less than $5900?

My solution:

Z=x-mean/Standard deviation= 5900-6058/500= -0.316 _ check the table

Thus, z is -0.48

P(X<5900)= P(Z<-0.48)= P(Z>0.48)= 1-0.6844= 0.3156

Therefore, the probability is 0.3156 or 31.56%