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I'm stuck on f, the function is defined at the top. Any help would be appreciated. Thank you! The problems on this page continue to

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I'm stuck on f, the function is defined at the top. Any help would be appreciated. Thank you!

image text in transcribed
The problems on this page continue to refer to f (x) = x3 + 2x2 - 4x + 1. f'( X ) = 3 *2+4x - 4 d) Without graphing, find the intervals of concavity of f. (-10, -2/3) -2/3 (-2/3, 00) f " ( x ) = 6 x + 4 t. V 0 = 6*+ 4 F " (x ) + +4 - 4 = 6x Down Up X = - 4. =-2 concare down: (-0, 3) Concave up: ( - 38, 00 ) e) Without graphing, find the inflection point(s) of f. f ( - 3 ) = (3 )+ 2(- 3) - 4(-3 ) +1 27 +3 + 8 + 1 - 8+ (8 .3) +(8.9) +27 - - 8+24+72+27 1 27 27 27 inflection points = (s, t f) Without graphing, make a list of at least two intervals where the Extreme Value Theorem holds

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