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QUESTION 2 Question 2 (AV) 0.5 / 2 pts QUESTION 3 Question 3 (Sketch a graph) 2/3 pts QUESTION 4 Question 4 (Evaluate reasoning) 2/ 2 pts QUESTION 5 Question 5 (Instantaneous estimate) 1/3 pts + 1 pt Successfully computed average velocity over a small interval. + 1 pt Explained process of estimating instantaneous velocity. v +1 pt Justified positive (or negative or 0) velocity result. + 0 pts No response. This response goes beyond the scope of the question; we'd like to see evidence of an ability to estimate Instantaneous velocity without having access to a formula for the function. QUESTION 6 Question 6 (Velocity graph) 1/ 4 pts QUESTION 7 Question 7 (Connections) 3 / 3 pts Q Next Question > Submission History C Request Regrade092932/SUBMISSIO 5. Using your graph, estimate the instantaneous horizontal velocity of the skateboarder at / = 3.5 seconds after the video starts. Should this velocity be positive or negative? Why? At t-3.5 s the distance is decreasing which means the velocity is negative. The equation of the position time graph can be estimated the equation is of's trigonometric form The position varies from 0 to 20. Thus amplitude is 10. The is a phase shift of -(n/2) and there is a vertical shift of 10 x(1)=10sin(1+0)+10 10sin(t -(n/2))+ 10 Velocity is the derivative of of position with respect to time v(t)= d/dt(x(t)) v(t)= d/dt(10sin(t -(n/2)+10) v(t)= 10cos(t -(1/2)) When 1-3.5s 978-3. 5mus\fSkateboarder's Position 25 E 20 Horizontal Distance, m 15 10 0 2 6 8 10 12 14 16 18 20 time, 5 The forward direction from 0 m towards 20 m and backward direction from 20 m to 0 m