Imagine you were to repeat the last experiment/exploration in today's lab but instead of spinning the charged Teflon rod with another charged rod you set up a torque balance as shown in the picture below. You wrapped the string around the top of the spinner which has the radius r=15mm. You brought another charged rod (not shown in the picture) distance d=1.5cm from the very tip of your test rod and hung a small weight m on the end of the string. The entire system is in balance, that is neither the weight nor the rod are moving. The length of the rod is L=23cm, the amount of charge on each rod is Q=9 10-8 C, gravitational constant g=9.8m/s and vacuum permeability 0 = 8.85 10-12 F/m. Making the same assumptions about the interaction between the rods as you did in the lab (treating the tips of the rod as point charges) what is the mass of the weight m did you have to hang to balance the system? m = g (that is grams)