Implement LLAddressBook.java using array(s). Instead of using Linked Lists, you will use arrays. You can use any approach, however, you must store the data in array(s).

Hint: You can use three different arrays for firstName, lastName and phoneNumber. Index numbers of an entry in each array would be the same.

The LLAddressBook.Java is below.

package cs260_02122020;

public class LLAddressBook {

//data members private AddressNode log; private String name; //constructors public LLAddressBook(String initFirstName, String initLastName, String initPhoneNumber, String initName) { //create a new addressNode with given parameters log = new AddressNode(initFirstName, initLastName, initPhoneNumber); name = initName; } //methods public String toString() { String result = ""; AddressNode currNode; currNode = log; //go into the loop to collect strings... while (currNode != null) { result += currNode.toString() + ' '; currNode = currNode.getNextNode(); } return name + ": " + result; } //insert method public void insert(String newLastName, String newFirstName, String newPhoneNumber) { //step 1: create a new node AddressNode newNode = new AddressNode( newLastName, newFirstName, newPhoneNumber); //step 2: set its nextNode to log newNode.setNextNode(log); //step 3: set log to this newNode (last step!) log = newNode; } public void clear() { log = null; } //searching by the lastName public boolean search(String targetLastName) { AddressNode currNode; currNode = log;//start from the first noed boolean result = false; while (currNode != null) { if(targetLastName.equalsIgnoreCase(currNode.getLastName())) { return true; } currNode = currNode.getNextNode(); } return false; } }

Thing is theres a whole folder of code that was given to me along with the assignment so I cant upload it all here since it would be a lot. If anyone can please help me answer this question, id be able to send the file to you if you reply to me with a contact.