IMPORTANT,:::::::: i got for w $740$ kmol$/$hr but hereis diff whyExample $2$: The mixture that contains $30$ mole $\%$ n$-$pentane and the remainder $n-$hexane is fed to a distillation column to recover $90\%$ of the $n-$pentane in the top and $90\%$ n$-$hexane in the bottom. The feed enters the column at a rate of $1000$Kmo$\frac{l}{h}.$ Calculate the outlets mole flow rate

Solution

$n-$pentane $(A)$ enter in feed $=0\mathrm{.}31000=300$kmo$\frac{l}{h}r$

$n-$hexane $(B)$ enter in feed $=0\mathrm{.}71000=700$kmo$\frac{l}{h}r$

$n-$pentane $(A)$ in distillate $=3000\mathrm{.}9=270$kmo$\frac{l}{h}r$

$n-$pentane $(A)$ in bottom $=3000\mathrm{.}1=30$kmo$\frac{l}{h}r$

$n-$hexane $(B)$ in bottom $=7000\mathrm{.}9=630$kmo$\frac{l}{h}r$

$n-$hexane $(B)$ in distillate $=7000\mathrm{.}1=70$kmo$\frac{l}{h}r$