In 2010, 10% of all U.S. families had incomes below the poverty level, as reported by the U.S. Census Bureauin American Community Survey. During that same year, of 381 randomly selected North Dakota families, 44 had incomes below the poverty level. At the 5% significance level, do the data provide sufficient evidenceto conclude that, in 2010, the percentage of families with incomes below the poverty level among those living in North Dakota was different from than among all U.S. families?

1) Procedure: One proportion Z Hypothesis Test? One mean Z Hypothesis Test? One mean T Hypothesis Test? One variance Hypothesis Test?

2) Assumptions: (select everything that applies)

• The conditions np and nq are both greather than or equal to 5 are satisfied
• Simple random sample
• Sample size is greater than 30
• Normal population
• The conditions for a binomial distribution are satisfied
• Population standard deviation is known
• Population standard deviation is unknown

3) Step 1. Hypotheses Set-Up:

H0: p? ? ? = _______	, where ? p? ? is the population mean? population variance? population proportion? and the units are 100%? subjects?
Ha: p? ? ? > < _______	, and the test is Two-Tail? Right-Tail? Left-Tail?

4) Step 2. The significance level = _____ %

5) Step 3. Compute the value of the test statistic: f? z? t? ? = _______ (Round the answer to 2 decimal places)

6) Step 4. Testing Procedure: (Round the critical value to 2 decimal places and the P-value to 4 decimal places)

CVA	PVA
Provide the critical value(s) for the Rejection Region (Type DNE if a CV is not needed):	Compute the P-value of the test statistic:
left CV is ______ and right CV is _______	P-value is ______

7) Step 5. Decision:

CVA	PVA
Is the test statistic in the rejection region?	Is the P-value less than the significance level?
no? yes?	no? yes?

8) Conclusion: Do not reject the null hypothesis in favor of the alternative? Reject the null hypothesis in favor of the alternative?

9) Step 6. Interpretation:

At 5% significance level we DO NOT? DO? have sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis.