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In 2012, 1,664,479 students took the SAT exam. The distribution of scores in the verbal section of the SAT had a mean= 496 and a

In 2012, 1,664,479 students took the SAT exam. The distribution of scores in the verbal section of the SAT had a mean= 496 and a standard deviation= 114. Let X = a SAT exam verbal section score in 2012. Then X ~ N(496, 114).

Find the z-scores for

a) x1 = 325z=__________to the nearest tenth

and x2 = 366.21z=_________to the nearest hundredth.

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