In a certain city the temperature (in F) t hours after 9 AM was modeled by the function T{t) = 57 + 20 sin(). 12 Find the average temperature Tave during the period from 9 AM to 9 PM. Step 1 Let 9:00 AM correspond to t = 0 hours. Then, 9:00 PM corresponds to t = I ,9- hours. Step 2 1 I .wl _ - - 111' We must nd Tave I I i\"- _ of (57 + 20 sm(_)) dt. 0 12 Step 3 Using properties of the integral, we know the following. 12 12 12 (57 + 20 sin() )dt = 57 d: + 20 sin() dt [l 12 0 12 By evaluating the first integral, we get [12 [ 57+40 ]12 57dt = a TI: Submit | Skip {you cannot come back)