In a completely randomized design, eight experimental units were used for each of the five levels of the factor. Consider the following ANOVA table. Source Sum Degrees Mean F Square p-value of Variation of Squares of Freedom Treatments 320 4 80 21.54 0.0000 Error 130 35 3.71 Total 450 39 (a) What hypotheses are implied in this problem? O Ho: At least two of the population means are equal. Ha: At least two of the population means are different. OH: M1 = H2 = M3 = HA = 15 Ha: H1 # H2 # H3 # 14 # 15 O Ho: My = H2 = M3 = HA = 15 H: Not all the population means are equal. OH: My # 12 # H3 # HA # 15 Ha: H1 = H2 = M3 = H4 = H5 O Ho: Not all the population means are equal. Ha: H1 = H2 = H3 = H4 = 15 (b) At the a = 0.05 level of significance, can we reject the null hypothesis in part (a)? Explain. O Because the p-value a = 0.05, we cannot reject Ho. Because the p-value S a = 0.05, we cannot reject Ho. O Because the p-value > a = 0.05, we can reject Ho