In a Leichtman Research Group survey of 1050 TV households, 74.6% of them had at least one Internet-connected TV device (for example, Smart TV, standalone streaming device, connected video game console). A marketing executive wants to convey high penetration of Internetconnected TV devices, so he makes the claim that the percentage of all homes with at least one Internet-connected TV device is equal to 77%. Test that claim using a 0.01 signicance level. Use the Pvalue method. Use the normal distribution as an approximation to the binomial distribution. ...) Let p denote the population proportion of all homes with at least one Internetconnected TV device. Identify the null and alternative hypotheses. H0:p = .77 H1: p 5E .77 (Type integers or decimals. Do not round.) Identi'y the test statistic. FD (Round to two decimal places as needed.) Identify the Pvalue. P-value = Cl (Round to three decimal places as needed.) State the conclusion about the null hypothesis, as well as the nal conclusion that addresses the original claim. Fail to reject the null hypothesis. There sufcient evidence to warrant rejection of the claim that the percentage of all homes with at least one Internet-connected TV device is equal to 77%